Monday, December 27, 2010

CrazyEngineers Forum

CrazyEngineers Forum

CrazyEngineers Forum

Regarding SAS Software---- urgent

Posted: 27 Dec 2010 10:48 AM PST

Hello ,
I want to learn about this software but don't know which book to consult . As I am beginner and know nothing about this software please suggest me some books to learn about this software .
:confused:

GRE Dates Running Out

Posted: 27 Dec 2010 10:09 AM PST

For those who plan to take the old GRE pattern test, book /register for the test as soon as possible. The dates are running out and there will obviously be a huge rush for in July as it will be the last month in which exams for the old pattern could be taken.

Locate the nearest test center, the one you are comfortable with. It could be the case that the center where you planned to give the test are already full. In that case, look for the best possible center and book your seats.

PS: Passport is not necessary while booking the seat. All you need is a net connection and an international credit/master card.

So hurry! :D

Can it be convergent?

Posted: 27 Dec 2010 09:52 AM PST

4) The value of ¾ + 5 / 36 + 7 / 144 + …….+17 / 5184 + 19 / 8100 is
a) 0.99 b) 0.98 c) 0.95 d) None of these

Steam turbine & generator arrangement _alastom

Posted: 27 Dec 2010 09:52 AM PST

this file (.pdf) format , explain the arrangement of steam turbine and generator yard , with all of its components in easy view from , alastom company.



Quote:
steam turbine & generator arrangement _alstom

STG Arrangement.pdf


for more about
(thermal power station , steam power plant, electricity production , operation and commissioning)

you can visit
Thermal Power Station , Steam Power Plant , Electricity Production , Operation and Commissioning

Three runners : Do they ever meet??

Posted: 27 Dec 2010 09:47 AM PST

In a circular race track of length 100 m, three persons A, B and C start together. A
and B start in the same direction at speeds of 10 m/s and 8 m/s respectively. While C
runs in the opposite at 15 m/s. When will all the three meet for the first time on the after
the start?

a) After 4 s
b) After 50 s
c) After 100 s
d) After 200 s

Plz solve it...

Find the relation

Posted: 27 Dec 2010 09:08 AM PST

Mary's mother's brother's brother-in-law is also her _______.

What is Rf Modules?

Posted: 27 Dec 2010 07:52 AM PST

Dear friends!
Would you plz explain what is rf modules as in their application and scope and future tech??
I will be thankfull..:p

Intelligent Vehicular Monitoring Using Multi-Hop Wireless System

Posted: 27 Dec 2010 07:26 AM PST

Vehicular Monitoring Using Multi-Hop Wireless System


ABSTRACT:-

The accurate location of the accident spot is the key for the correct evaluation of a link between road and accident process and for right choice of improvement measures in vehicular monitoring systems.
A Multi-hop based wireless adhoc network of nodes can disseminate critical safety information in alert packets. The nodes can be embedded in vehicles. The alert can be used to trigger emergency responses resources. For example, the network can signal unusual events such as accidents, disabled vehicles or road obstructions to operators in nearby vehicles. When the vehicles are equipped with the wireless nodes, the information can easily be broadcast and propagated along the road until the desired destination service center is reached.
Now this concept is used in vehicular accidents to get a medical emergency assistance. When an accident occurs on a road, this is sensed as an event in both victimized vehicles (source node) and an alert packet is broadcast in response to sensing the event. This alert packet is received by a set of candidate nodes (nearby passing vehicles) within a broadcast range of a source node. Each candidate node infers distance between the candidate node and the source node based on the receive power of received alert packet and determines a priority for rebroadcasting the alert packet, wherein the priority is based on the distance to minimizing a probability of collisions while rebroadcast the alert packet and extend a range of the broadcasting.

INTRODUCTION:-

Hop is a method of wireless communication between two nodes. There are levels in hopping namely frequency hopping and multi hopping. Frequency hopping is a technique in which binary data sequence carrying information modulates the frequency of carrier signal resulting in FSK signal. A group of 'k' binary bits and a set of 2k subcarrier frequencies are chosen to generate a multi level FSK. This MFSK finally modulates a carrier which hops randomly. By choosing a large number of randomly hopping discrete carrier frequencies it is possible to have a modulated signal of wide bandwidth which in turn results in large processing gain.
Frequency hopping operates between only two nodes so we look for much enhanced operation between multiple nodes hence the improved technology that developed on the basis of frequency hopping called as "Multi HOP '' communication.
Multi Hop communication works on the principle of frequency hop such that each node can communicate with multiple nodes simultaneously i.e., each transmitter can communicate with one or more receivers at a time.
Multi Hop wireless communication system which synchronizes a time signal generated by a timer device included in each of the wireless terminals and sets a different active timing signal to a wireless terminal connected each of a plurality of Multi Hop routes. The wireless terminal monitors the time signal of timer device
included in the wireless terminal and activates the wireless communication of the wireless terminal when it is detected such that the timing signal matches an active timing set in the wireless terminal.

GPS:- A tracking system employing global positioning system (GPS) satellites provides extremely accurate position, velocity, and time information for vehicles or any other animate or inanimate object within any mobile radio communication system or information system, including those operating in high rise urban areas. The GSM Modem used with the GPS receiver is used for sending SMS. The GPS receiver calculates the latitude and longitudinal values which are transmitted over to the user mobile through the GSM device.


Intelligent Vehicular Monitoring Using Multi-Hop Wireless System

Posted: 27 Dec 2010 07:23 AM PST

Intelligent Vehicular Monitoring Using Multi-Hop Wireless System
ABSTRACT:-

The accurate location of the accident spot is the key for the correct evaluation of a link between road and accident process and for right choice of improvement measures in vehicular monitoring systems.
A Multi-hop based wireless adhoc network of nodes can disseminate critical safety information in alert packets. The nodes can be embedded in vehicles. The alert can be used to trigger emergency responses resources. For example, the network can signal unusual events such as accidents, disabled vehicles or road obstructions to operators in nearby vehicles. When the vehicles are equipped with the wireless nodes, the information can easily be broadcast and propagated along the road until the desired destination service center is reached.
Now this concept is used in vehicular accidents to get a medical emergency assistance. When an accident occurs on a road, this is sensed as an event in both victimized vehicles (source node) and an alert packet is broadcast in response to sensing the event. This alert packet is received by a set of candidate nodes (nearby passing vehicles) within a broadcast range of a source node. Each candidate node infers distance between the candidate node and the source node based on the receive power of received alert packet and determines a priority for rebroadcasting the alert packet, wherein the priority is based on the distance to minimizing a probability of collisions while rebroadcast the alert packet and extend a range of the broadcasting.

embedd flash in php based website

Posted: 27 Dec 2010 06:52 AM PST

hello,

i am making my own website in php and in order to make it a quite attractive one i want to know how one can use pages (designed in flash) in php based website.

thank you

RSA Encryption

Posted: 27 Dec 2010 06:11 AM PST

One commonly used cipher of this forms called RSA Encryption,
where RSA are the initials of the three creators: Rivest, Shamir, and Adleman. It
is based on the following idea:
It is very simply to multiply numbers together, especially with computers. But it can
be very difficult to factor numbers. For example, if I ask you to multiply together
34537 and 99991, it is a simple matter to punch those numbers into a calculator and
3453389167. But the reverse problem is much harder.
Suppose I give you the number 1459160519. I'll even tell you that I got it by multi-
plying together two integers. Can you tell me what they are? This is a very difficult
problem. A computer can factor that number fairly quickly, but (although there are
some tricks) it basically does it by trying most of the possible combinations. For any
size number, the computer has to check something that is of the order of the size of
the square-root of the number to be factored. In this case, that square-root is roughly
38000.
Now it doesn't take a computer long to try out 38000 possibilities, but what if the
number to be factored is not ten digits, but rather 400 digits? The square-root of a
number with 400 digits is a number with 200 digits. The lifetime of the universe is
approximately 10^18 seconds an 18 digit number. Assuming a computer could test
one million factorizations per second, in the lifetime of the universe it could check
10^24 possibilities. But for a 400 digit product, there are 10^200 possibilties. This means
the computer would have to run for 10^176 times the life of the universe to factor the
large number.
It is, however, not too hard to check to see if a number is prime in other words to
check to see that it cannot be factored. If it is not prime, it is difficult to factor, but if it
is prime, it is not hard to show it is prime.
So RSA encryption works like this. I will find two huge prime numbers, p and q that
have 100 or maybe 200 digits each. I will keep those two numbers secret (they are
my private key), and I will multiply them together to make a number N = pq. That
number N is basically my public key. It is relatively easy for me to get N; I just need
to multiply my two numbers. But if you know N, it is basically impossible for you
to find p and q. To get them, you need to factor N, which seems to be an incredibly
difficult problem.
But exactly how is N used to encode a message, and how are p and q used to decode
it? Below is presented a complete example, but I will use tiny prime numbers so it is
easy to follow the arithmetic. In a real RSA encryption system, keep in mind that the
prime numbers are huge.

how to call a three procedures in a single statement?

Posted: 27 Dec 2010 06:05 AM PST

I am currently facing this problem. i have to write a single callable statement that will call three procedures and calling second procedure from first procedure is not a option . please help.

What's The Ultimate In Communication?

Posted: 27 Dec 2010 05:21 AM PST

Not exactly a debate topic, but I'm sure we'll have many interesting opinions. That's the reason I'm starting the topic in Debate section -

I've been wondering what could be the ultimate discovery in communication. I believe it's definitely going to be 'Telepathy'.

Communication is essentially about exchange/transfer of thoughts. If (crazy)engineers and scientists ever discover a way to directly communicate to each others minds, there won't be a need of telephone or for that matter sound to communicate.

Just a thought that popped up in my mind, I'll elaborate it later. I look forward to your views.

Vector analysis

Posted: 27 Dec 2010 05:00 AM PST

Who has problems with answers regarding vector analysis specifically about dot and cross product???

Refrigeration and Airconditioning

Posted: 27 Dec 2010 03:30 AM PST

Moist air at 40°C and 90% R.H. enters a dehumidifier at the rate of 300 m3/min. The condensate and the saturated air exit at 10°C through separate exits. The pressure remains constant at 100 kPa. Determine: (a) the mass flow rate of dry air,
a. 431 kg/min b. 311.61 kg/min c. 278.42 kg/min d. 196 kg/min e. none
(b) the water removal rate, and
a. 11.4 kg/min b. 13.5 kg/min c. 24.2 kg/min d. 19.6 kg/min e. none
(c) the required refrigeration capacity in tons.
a. 221.69 tons b. 310.75 tons c. 181.91 tons d. 257.13 tons e. none

An air-conditioned space is supplied 10 000 ft3/min (283 m3/min) of air at 65°F (18.3°C) and 60% relative humidity. Air is supplied to the dehumidifier at 85°F (29.4°C); wet-bulb temperature is 70°F (21.1°). Condensate leaves the dehumidifier at the same temperature as the outgoing air, which is at standard atmospheric pressure throughout the system. Air leaves the dehumidifier in the same saturated state. Determine the refrigerating load for this air-conditioned space.
a. 28.9 tons b. 39.5 tons c. 48.7 tons d. 51.3 tons e. none


Those are my problems. My professor does not teach us how to solve these kind of problems. I read books, and try to solve, but I did not get the answer. Please show me how to solve these problems.
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